The equilibrium constant of the reaction-Cu s -2 Ag - aq - Cu 2- aq -2 Ag s - E -0-46 V at 298 K is -A- 4-0 - 1015B- 2-4 - 1010- 2-0 - 1010D- 4-0 - 1010

The correct option is A 4.0 × 10^15 Δ G^∘ = n × F × e = 2 × 96500 × 0.46 = 88780J Δ G^∘ = 2.303 RT log K_c or 88780 = 2.303 × 8.314 × 298 log K_c or 8 ...

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Standard XII

Physics

Calorimetry

The equilibri...

Question

The equilibrium constant of the reaction:

$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s); E^{\circ} = 0.46 V$ at 298K is :

$4.0 \times 10^{15}$

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$2.4 \times 10^{10}$

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$2.0 \times 10^{10}$

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$4.0 \times 10^{10}$

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Solution

The correct option is A
$4.0 \times 10^{15}$

$Δ G^{\circ} = - n \times F \times e = - 2 \times 96500 \times 0.46 = - 88780 J$

$Δ G^{\circ} = 2.303 R T l o g K_{c}$

$o r - 88780 = - 2.303 \times 8.314 \times 298 l o g K_{c}$

$o r - 88780 = - 5705.84 l o g K_{c}$

$⟹ l o g K_{c} = 15.55 \Rightarrow [K_{c} \approx 4 \times 10^{15}]$

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Similar questions

Q. The equilibrium constant of the reaction:

C u (s) + 2 A g^{+} (a q) ⇌ C u^{2 +} (a q) + 2 A g (s)

E^{\circ} = 0.46 V

298 K

is:

Q. The equilibrium constant of the reaction;

C u (s) + 2 {A g}^{+} (a q) ⟶ {C u}^{2 +} (a q) + 2 A g (s)

E^{o} = 0.46 V

298 K

Calculate the equilibrium constant of the reaction.
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$ , $E_{c e l l}^{⊖} = 0.46 V$

Q. The equilibrium constant for the equation:

E^{0} = 0.46 V

at 298 K is:

C u + 2 A g^{+} (a q) ⟶ {C u}^{2 +} (a q) + 2 A g

C u (s) + 2 {A g}^{+} (a q) \to {C u}^{2 +} (A q) + 2 A g (s)

The equilibrium constant

(K)

for the above reaction will be:

[ Given,

E_{c e l l}^{\circ} = 0.46 V

]

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The equilibrium constant of the reaction: Cu(s)+2Ag+(aq)→Cu2+(aq)+2Ag(s);E∘=0.46V at 298K is :

The correct option is A 4.0×1015 ΔG∘=−n×F×e=−2×96500×0.46=−88780J ΔG∘=2.303 RT log Kc or−88780=−2.303×8.314×298 log Kc or −88780=−5705.84logKc ⟹logKc=15.55⇒[Kc≈4×1015]

The equilibrium constant of the reaction:

$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s); E^{\circ} = 0.46 V$ at 298K is :