The equilibrium constant of the reaction- SO3g- SO2g - 12O2g- is 0-20 mole1-2 -litre-1-2 at 1000 K- Calculate equilibrium constant for 2SO2g - O2g- 2SO3g-

For SO_3(g)⇌ SO_2(g) + 12 O_2(g) K_c_1 = [SO_2][O_2]^1/2[SO_3] = 0.20 .... (1) For 2SO_2 + O_2⇌ 2SO_3 K_c = [SO_3]^2[SO_2]^2[O_2] ... (2) By ...

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Molality

The equilibri...

Question

The equilibrium constant of the reaction; $S O_{3 (g)} ⇌ S O_{2 (g)} + \frac{1}{2} O_{2 (g)}$ ; is $0.20 m o l e^{\frac{1}{2}} . l i t r e^{\frac{- 1}{2}}$ at $1000 K$ . Calculate equilibrium constant for $2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}$ .

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S O_{3 (g)} ⇌ S O_{2 (g)} + \frac{1}{2} O_{2 (g)},

0.20 m o l e^{1 / 2} l i t r e^{- 1 / 2}

1000 K

S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

{S O}_{3} (g) ⇌ {S O}_{2} (g) + \frac{1}{2} O_{2} (g)

2 {S O}_{2} (g) + O_{2} (g) ⇌ {2 S O}_{3} (g)

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {S O}_{3} (g)

K_{c}

1.7 \times 10^{12}

300 K

300 K

2 S O_{2} (g) + O_{2} (g) ⇌ 2 {S O}_{3} (g)

{S O}_{3} (g) ⇌ S O_{2} (g) + \frac{1}{2} O_{2} (g)

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

S O_{3} (g) ⇌ S O_{2} (g) + \frac{1}{2} O_{2} (g)

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

4 \times 10^{- 3} a t m^{- 1 / 2} .

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

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