The equilibrium constants for A2g - 2Ag at 400 K and 600 K are 1 - 10-8 and 1 - 10-2 respectively- The reaction is-

The correct option is A endothermic A _ 2 (g)⇌ 2A(g) At 400 K, K= 1 × 10^ 8 At 600 K, K= 1 × 10^ 2 (which is more)Hence, more reaction occurs at 6 ...

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Standard XII

Chemistry

Le Chatelier's Principle for Del N Equals to 0

The equilibri...

Question

The equilibrium constants for $A_{2} (g) ⇌ 2 A (g)$ at $400$ K and $600$ K are $1 \times 10^{- 8}$ and $1 \times 10^{- 2}$ respectively. The reaction is:

exothermic

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endothermic

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may be exothermic or endothermic

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no heat is evolved or abosorbed

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Solution

The correct option is A endothermic
$A_{2} (g) ⇌ 2 A (g)$
At 400 K, K= $1 \times 10^{- 8}$
At 600 K, K= $1 \times 10^{- 2}$ (which is more)
Hence, more reaction occurs at 600 K. Hence the reaction is endothermic.

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The equilibrium constants for A2(g)⇌2A(g) at 400 K and 600 K are 1×10−8 and 1×10−2 respectively. The reaction is:

The correct option is A endothermicA2(g)⇌2A(g)At 400 K, K=1×10−8At 600 K, K=1×10−2 (which is more)Hence, more reaction occurs at 600 K. Hence the reaction is endothermic.

The equilibrium constants for $A_{2} (g) ⇌ 2 A (g)$ at $400$ K and $600$ K are $1 \times 10^{- 8}$ and $1 \times 10^{- 2}$ respectively. The reaction is:

The correct option is A endothermic
$A_{2} (g) ⇌ 2 A (g)$
At 400 K, K= $1 \times 10^{- 8}$
At 600 K, K= $1 \times 10^{- 2}$ (which is more)
Hence, more reaction occurs at 600 K. Hence the reaction is endothermic.