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Ideal Gas Equation

The equilibri...

Question

The equilibrium established in a reaction vessel of $2.5$ L capacity. The amounts of $N_{2}$ and $O_{2}$ taken at the start were respectively $2$ moles and $4$ moles. Half a mole of nitrogen has been used up at equilibrium. The molar concentration of nitric oxide is:

$N_{2} + O_{2} ⇌ 2 N O$

A

0.2

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B

0.4

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C

0.6

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D

0.1

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Solution

The correct option is A $0.4$
$N_{2} + O_{2} ⇌ 2 N O$

Time= $0$ $2$ mol $4$ mol

Time= $e q 2 - α 4 - α 2 α$
$∵ α = 0.5 m o l e$

$2 - 0.5 4 - 0.5 2 (0.5)$

$M o l a r i t y = \frac{N o . o f m o l e s}{V o l u m e o f s o l u t i o n (L)}$

$M o l e s o f N O = 2 \times 0.5$
$= 1$

Volume given = $2.5 L$

Molar concentration of nitric Oxide is $\frac{1}{2.5} = 0.4 M$

Hence, option $B$ is correct.

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