You visited us 5 times! Enjoying our articles? Unlock Full Access!

Conservative and Non Conservative Forces

The equilibri...

Question

The equilibrium established when $H g C l_{2}$ is shaken with an excess of $H g$ is:

H g^{2 +} + H g ⇌ 2 H g^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H g^{2 +} + H g_{(l)} ⇌ H g_{2}^{2 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H g + 2 H g^{2 +} ⇌ H g^{2 +} + 2 H g^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

no equilibrium is established

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H g^{2 +} + H g_{(l)} ⇌ H g_{2}^{2 +}$
As we have given that $H g_{2}^{+ 2}$ disproportionates and forms $H g_{(l)} a n d H g^{+ 2}$ at equilibrium , so If we take $H g C l_{2}$ and $H g$ it will comproportionate and $H g_{2}^{+ 2}$ will form at equilibrium.
So, answer is B.

Suggest Corrections

Similar questions

H g_{2}^{2 +} + 2 e^{-} \to 2 H g ⟹ E^{0} = 0.789 V

H g^{2 +} + 2 e^{-} \to H g ⟹ E^{0} = 0.854 V

H g_{2}^{2 +} \to H g + H g^{2 +}

H g^{2 +} + H g \to H g_{2}^{2 +}

E_{(H g | H g^{2 +})}^{⊖} = - 0.788 V; E_{(H g_{2}^{2 +} | 2 H g^{2 +})}^{⊖} = - 0.92 V

K_{e q} = 2.98 \times 10^{x}

x

H g

10^{- 3} M

F e^{3 +}

4.6

F e^{3 +}

25^{\circ} C

E^{\circ}

2 H g / H g_{2}^{2 +}

25^{\circ} C

2 H g + 2 F e^{3 +} ⇌ H g_{2}^{2 +} + 2 F e^{2 +}

K_{c}

H g^{2 +} + H g ⇌ H g_{2}^{2 +}

E_{2 H g / H g^{2 +}}^{o} = - 0.788 V

E_{H g_{2}^{2 +} / 2 H g^{2 +}}^{o} = - 0.920 V

H g

H g^{1 +}

H g^{2 +}

Join BYJU'S Learning Program