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Question

The equilibrium mixture, SO3(g)+NO(g)SO2(g)+NO2(g) contains 0.6 mol of SO3, 0.4 mol of No, 0.8 mol of SO2 and 0.1 mol of NO2 per litre. If 1 mol of NO is introduced into the reaction vessel, then the number of moles of SO3,NO,SO2 and NO2 of each gas in the new equilibrium in moles per litre will be:

A
0.48, 1.3, 0.92 and 0.22
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B
0.48,1.3.0.92 and 2.2
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C
0.48,0.13.092 and 0.22
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D
4.8,1.3,0.92 and 0.22
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Solution

The correct option is A 0.48, 1.3, 0.92 and 0.22
SO3(g)+NO(g)SO2(g)+NO2(g)
No of moles 0.6 0.4 0.8 0.1
At equilibrium +1
1.4
Conc. Of reactant decreases, conc. of product increases according Le-Chatelier’s principle

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