The equilibrium of the reaction N2 g -3H2 g - 2NH3 g will shift to the product side when-

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Law of Mass Action

The equilibri...

Question

The equilibrium of the reaction $N_{2} (g) + 3 H_{2} (g) \Leftrightarrow 2 N H_{3} (g)$ will shift to the product side when:

K_{p} > 1

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Q < K_{p}

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Q = K_{p}

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Q < 2 K_{p}

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Solution

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Similar questions

N_{2} (g) + 3 H_{2} (g) \Leftrightarrow 2 N H_{3} (g)

K_{p}

K_{p}^{'}

\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ {N H}_{3} (g)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

K_{p}

K_{p}^{'}

For $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g) + h e a t$

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

K_{p}

2 N H_{3} (g) ⇌ N_{2} (g) + 3 H_{2} (g),

K_{p}

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