Question

The equivalent capacitance across $\text{AB}$ is:

• A. $\frac{3C}{5}$
  
• B. $\frac{5C}{3}$
  
• C. $\frac{2C}{5}$
  
• D. $3C$

Answer 1

The correct option is B $\frac{5C}{3}$


The capacitors across $\text{OD}$ and $\text{OE}$ are parallel to each other. So, theie equivalent capacitance for them will be $(C+C=2C)$ is shown in the figure.


Now, the capacitors across $\text{AO}$ and $\text{OB}$ are in series. Since the points $\text{B}$ and $\text{D,E}$ are connected by single wire so, the their potential will be same. Redrawing the circuit,


Now, equivalent capacitaoss across $\text{AB}$,

$(C_{eq}{)}_{AB}=\frac{2C}{3}+C=\frac{5C}{3}$

Hence, option (b) is correct answer.