The equivalent capacitance between points $A$ and $B$ will be

10 μ F

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15 μ F

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10.8 μ F

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69 μ F

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Solution

The correct option is A $10 μ F$
The given circuit can be redrawn as
It is a balance Wheatstone bridge type network
i.e., $\frac{C_{1}}{C_{2}} = \frac{C_{3}}{C_{4}} = \frac{1}{2}$
$∴ 24 μ F$ capacitor can be neglected
Hence, equivalent capacitance between $A$ and $B = 4 + 6 = 10 μ F$ .

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The equivalent capacitance between points A and B will be

The correct option is A 10μFThe given circuit can be redrawn asIt is a balance Wheatstone bridge type networki.e., C1C2=C3C4=12∴24μF capacitor can be neglectedHence, equivalent capacitance between A and B=4+6=10μF.

The equivalent capacitance between points $A$ and $B$ will be

The correct option is A $10 μ F$
The given circuit can be redrawn as
It is a balance Wheatstone bridge type network
i.e., $\frac{C_{1}}{C_{2}} = \frac{C_{3}}{C_{4}} = \frac{1}{2}$
$∴ 24 μ F$ capacitor can be neglected
Hence, equivalent capacitance between $A$ and $B = 4 + 6 = 10 μ F$ .