The equivalent capacitance between points X and Y in figure shown is :
A
65μF
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B
4μF
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C
185μF
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D
none of these
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Solution
The correct option is C185μF As the structure is balanced Wheatstone bridge, so 5μF capacitor will draw no charge from battery and may be removed. Now the circuit is a simple circuit. 4μF and 6μF are in series, then C1=(4×66+4) 3μF and 2μF are also in series, therefore C2=(3×23+2) Now C1 and C2 are in parallel Ceq=(4×66+4)+(3×23+2)=185μF