The equivalent capacitance between the terminals X and Y in the figure shown will be -
Let two nodes a, b between the terminal X and Y.
Since between the node Y and b the two capacitors of 100pf are in parallel, between the node a and b the capacitor of 200pf is in series.
The equivalent capacitance between the node Y and b is given as,
C1=100||100
=200pf
The equivalent capacitance between the node Y and a is given as,
C2=[(200×200)200+200||100]
=200pf
The equivalent capacitance between the node Y and X is given as,
C=[(200×200)200+200||100]
=200pf
Thus, the equivalent capacitance between the terminals X and Y is 200pf.