The equivalent capacitance for the network shown in the figure is:
A
3004pF
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B
10004pF
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C
18007pF
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D
13003pF
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Solution
The correct option is A3004pF Capacitance of C1=C4=100pF Capacitance of C2=C3=400pF Supply voltage, V=400V Capacitors C2 and C3 are connected in series Equivalent capacitance C′=1400+1400=2400 or C′=200pF Capacitors C1C′ are in parallel Their equivalent capacitance C′′=C′+C1=200+100=300pF Capacitors C′′ and C4 are connected in series Equivalent capacitance 1Ceq=1C′′+1C4=1300+1100 1Ceq=4300 ∴Ceq=3004pF