Question

The equivalent capacitance(in $\mu F$) between points $A$ and $B$ of the circuit will be (given : $C=1.3\mu F$)

Answer 1

$3.90$
Equivalent circuit of the above figure can be drawn as
Therefore, equivalent capacitance between $A$ and $B$ is $C_{eq}=\frac{6C\times 6C}{6C+6C}=3C$
But given that $C=1.3\mu F$
so, $C_{eq}=3\times 1.3=3.9\mu F$