The equivalent capacitance of the circuit across the terminals A and B is equal to :
A
0.5μF
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B
2μF
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C
1μF
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D
none of these
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Solution
The correct option is C1μF As shown in the figure, both capacitors C=2μF are in parallel so C1=2+2=4μF Now, capacitors C=2/3μF are also in parallel combination so C2=2/3+2/3=4/3μF C1 and C2 are now in series combination so Ceq=C1C2C1+C2=1μF