Question

The equivalent capacitance of the circuit across the terminals $A$ and $B$ is equal to :

• A. $0.5\mu F$
• B. $2\mu F$
• C. $1\mu F$
• D. none of these

Answer 1

The correct option is C $1\mu F$

As shown in the figure, both capacitors $C=2\mu F$ are in parallel so $C_1=2+2=4\mu F$
Now, capacitors $C=2/3\mu F$ are also in parallel combination so $C_2=2/3+2/3=4/3\mu F$
$C_1$ and $C_2$ are now in series combination
so $C_{eq}=\frac{C_1{C}_2}{C_1+C_2}=1\mu F$