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Question

# The equivalent conductance of 0.10 N solution of MgCl2 is 97.1 mho cm2equi−1 at 25∘C. A cell with electrode that are 1.5 cm2 in surface area and 0.5 cm apart is filled with 0.1 N MgCl2 solution. How much amperes of current will flow when potential difference between the electrodes is 5 volt?

A
0.6
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B
0.214
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C
0.321
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D
0.1456
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Solution

## The correct option is D 0.1456Given Δeq=97.1mhocm2equi−1Concentration of MgCl2=0.10N=CSurface Area (A) =1.5 cm2length (l) = 0.5 cmNow, Δeq=K×1000C 97.1=K×10000.1 K = 0.0097 mho cm2Now, R=ρlASince ρ=1K=10.0097=103.093ohm.cm R=103.093×0.51.5=34.36ohm According to ohm's Law V = IR V = 5 volt, R = 3.36 ohm 5=I×34.36 I=0.145AmpereHence option (D) is correct.

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