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Standard XII

Chemistry

Salt of Weak Acid and Strong Base

The equivalen...

Question

The equivalent conductivities at infinite dilution of the cation and the anion of a salt $A_{2} B$ are $140$ and $80$ $o h m^{- 1} c m^{2} e q^{- 1}$ respectively. The equivalent conductivity of the sal;t at infinite dilution is:

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Solution

$∵ Λ_{e q}^{\infty} = 2 Λ_{e q}^{\infty} (A^{+}) + Λ_{e q}^{\infty} (B^{-})$
$= 2 \times 140 + 80$
$Λ_{e q}^{\infty} (A_{2} B) = 3608. c m^{2} e q^{- 1}$

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The equivalent conductivities at infinite dilution of the cation and the anion of a salt A2B are 140 and 80 ohm−1 cm2 eq−1 respectively. The equivalent conductivity of the sal;t at infinite dilution is:

∵Λ∞eq=2Λ∞eq(A+)+Λ∞eq(B−) =2×140+80Λ∞eq(A2B)=3608.cm2eq−1

The equivalent conductivities at infinite dilution of the cation and the anion of a salt $A_{2} B$ are $140$ and $80$ $o h m^{- 1} c m^{2} e q^{- 1}$ respectively. The equivalent conductivity of the sal;t at infinite dilution is:

$∵ Λ_{e q}^{\infty} = 2 Λ_{e q}^{\infty} (A^{+}) + Λ_{e q}^{\infty} (B^{-})$
$= 2 \times 140 + 80$
$Λ_{e q}^{\infty} (A_{2} B) = 3608. c m^{2} e q^{- 1}$