Question

The equivalent conductivity of $0.1NCHNC{H}_{3}COOH$ at ${25}^{0}C$ is 80 and at infinite dilution it is 400, the degree of dissociation of $C{H}_{3}COOH$ is :

• A. 1
• B. 0.2
• C. 0.1
• D. 0.5

Answer 1

Answer: (B)

0.2

Given:-

${\wedge }_{eq}\left(C{H}_{3}COOH\right)=80Sc{m}^{-2}e{q}^{-1}$

${\wedge }_{eq}^{\infty }\left(C{H}_{3}COOH\right)$ at infinite dilution= $400Sc{m}^{2}e{q}^{-1}$

$\alpha ⟶$ Degree of dissociation

$\alpha =\frac{{\wedge }_{eq}^m}{{\wedge }_{eq}^{\infty }}=\frac{80}{400}=0.2$

$\alpha =0.2$