Question

The equivalent inductance of the network shown in the figure, between the points $a$ and $b$ is -

• A. $\frac{4H}{3}$
• B. $\frac{2H}{3}$
• C. $\frac{H}{3}$
• D. $H$

Answer 1

The correct option is A $\frac{4H}{3}$


We know that points connected directly with a wire are at the same potential.

Therefore, points $(b,c,d,e)$ are at the same potential.

On simplifying the given circuit, we get,


So, net inductance between points $o$ and $b$ is,

$L_{eq}=\frac{L}{3}=\frac{H}{3}$


Further, net inductance between points $a$ and $b$ is
$L_{eq}=L_1+L_2=H+\frac{H}{3}=\frac{4H}{3}$

Hence, option $\left(A\right)$ is the correct answer.