wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equivalent mass of a metal is 9 and vapour density of its chloride is 59.25. The atomic mass of metal is:

A
23.9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
27.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
36.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
48.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 23.9
Given equivalent weight of metal =9
Vapour density of metal chloride =59.25
molecular weight of metal chloride.
=2×V.D=2×59.25=118.5
valency of metal =molecular weight of metal chlorideequivalent weight of metal+35.5

valency of metal =118.59+35.5=118.544.5=2.66

Therefore, atomic weight of the metal = equivalent weight × valency
=9×2.66=23.9

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wave Nature of Light
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon