Question

The equivalent mass of a metal is $9$ and vapour density of its chloride is $59.25.$ The atomic mass of metal is:

• A. $23.9$
• B. $27.3$
• C. $36.3$
• D. $48.3$

Answer 1

The correct option is A $23.9$

Given equivalent weight of metal $=9$

Vapour density of metal chloride $=59.25$

$\therefore$ molecular weight of metal chloride.

$=2\times V.D=2\times 59.25=118.5$

$\therefore$ valency of metal $=\frac{\text{molecular weight of metal chloride}}{\text{equivalent weight of metal}+35.5}$

valency of metal $=\frac{118.5}{9+35.5}=\frac{118.5}{44.5}=2.66$

Therefore, atomic weight of the metal $=$ equivalent weight $\times$ valency

$=9\times 2.66=23.9$