Question

The equivalent mass of $A{s}_2{O}_3$ in the change, $A{s}_2^{3+}⟶A{s}_2^{5+}$ is $\frac{M}{x}$. Here, the value of $x$ is :

Answer 1

$A{s}_2^{3+}⟶A{s}_2^{5+}$
+3 +5
As we know,
$Equivalentweight=\frac{Molarweight}{n-factor}=\frac{M}{(2\times 2)}=\frac{M}{4}$.