Question

The equivalent mass of $H_{3}B{O}_3$ in its reaction with $NaOH$ to form $N{a}_2{B}_4{O}_7$ is equal to:

• A. (Molar mass)$/4$
• B. (Molar mass)$/3$
• C. (Molar mass)$/2$
• D. Molar mass

Answer 1

Answer: (D)

Molar mass

$H_{3}B{O}_3$ is a mono basic acid.

So,

Equivalent weight mass$=\frac{molecualrmass}{no.ofreplacebleH}$

$=\frac{M}{1}$

=Molar mass

$\therefore$ Option $D$ is correct.