Question

The equivalent mass of $HCl$ in the following reaction $K_{2}C{r}_2{O}_7+14HCl\to 2KCl+2CrC{l}_3+3C{l}_2+H_{2}O$ would be:

• A. $36.5$
• B. $73$
• C. $85$
• D. $16.25$

Answer 1

The correct option is C $85$

here $Cr$ shows a change in the oxidation of 6 for two chromium atom.

$\therefore f=6$

Equivalent weight$=\frac{\text{HCl}\times \text{number of atom oxidised or reduced}}{f}$

$=\frac{36.5\times 14}{6}$

$=85.167$

$\approx 85$