Question

The equivalent mass of $HClO$ in the reaction is :
$HClO+2l^{-}+H^{+}⟶C{l}^{-}+I_2+H_{2}O$

• A. 52.5
• B. 26.25
• C. 17.5
• D. 13.125

Answer 1

The correct option is B 26.25

Reaction:
$HClO+2I^{-}+H^{+}⟶C{l}^{-}+I_2+H_{2}O$
+1 -1
So, change in oxidation state is $2$ and eq. wt. of $HClO$ is $\frac{M}{2}=26.25$