Question

The equivalent mass of $MnS{O}_4$ is half of its molar mass when it is converted to :

• A. $M{n}_2{O}_3$
• B. $Mn{O}_2$
• C. $Mn{O}_4^{-}$
• D. $Mn{O}_4^{2-}$

Answer 1

The correct option is B $Mn{O}_2$

$MnS{O}_4\to Mn{O}_2$
+2 +4
So, Eq. wt. of $MnS{O}_4$ is $\frac{1}{2}\times$ molar mass.