The equivalent mass of Na2S2O3 as reductant in the reaction is Mx- Na2S2O3-5H2O-4Cl2-2NaHSO4-8HClThe value of x is -

Na_2S_2O_3+5H_2O+4Cl_2⟶2NaHSO_4+8HCl #160; #160; #160; #160; #160;+2 #160; #160; #160; #160; #160; #160; #160; #160; ...

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Ion Electron Method

The equivalen...

Question

The equivalent mass of $N a_{2} S_{2} O_{3}$ as reductant in the reaction is $\frac{M}{x}$ ,

$N a_{2} S_{2} O_{3} + 5 H_{2} O + 4 C l_{2} ⟶ 2 N a H S O_{4} + 8 H C l$

The value of $x$ is _____.

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N a_{2} S_{2} O_{3}

N a_{2} S_{2} O_{3} + 5 H_{2} O + 4 C l_{2} ⟶ 2 N a H S O_{4} + 8 H C l

N a_{2} S_{2} O_{3} + 4 C l_{2} + 5 H_{2} O \to N a_{2} S O_{4} + 8 H C l

N a_{2} S_{2} O_{3}

=

N a_{2} S_{2} O_{3}

(N a_{2} S_{2} O_{3} \cdot 5 H_{2} O)

2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}

N a_{2} S_{2} O_{3}

M

N a_{2} S_{2} O_{3} + H_{2} O + C l_{2} \to N a_{2} S O_{4} + 2 H C l + S

N a_{2} S_{2} O_{3}

N a_{2} S O_{3} + 4 C l_{2} + 5 H_{2} O \to N a_{2} S O_{4} + H_{2} S O_{4} + 8 H C l

N a_{2} S O_{3}

N a_{2} S O_{3}

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