The equivalent mass of oxidising agent in the following reaction is :
$S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O$

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Solution

The correct option is C 16
The reaction is as follows:
$S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O$
Change in oxidation state $= 4$ .
Here, $S O_{2}$ is an oxidising agent.
$4 e^{-} + S O_{2} ⟶ S$
So, equivalent of $S O_{2} = \frac{64}{4} = 16$ .

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