The equivalent resistance between A and B of network shown in figure is [UP CPMT 2

\frac{3 R}{4}

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\frac{4 R}{3}

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6 R

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2 R

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Solution

The correct option is D $\frac{3 R}{4}$
$R_{A B} = (\frac{R}{2} + R) | | (\frac{R}{2} + R)$

$= \frac{3 R}{2} | | \frac{3 R}{2} = \frac{3 R}{4}$

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The equivalent resistance between points a and b of a network shown in figure is given by

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