Question

The equivalent resistance between point A and B in the circuit shown is :

• A. R
• B. R/2
• C. R/4
• D. R/8

Answer 1

Answer: (B)

R/2

Let

$R_1=R{R}_2=R_3=2R$

After reducing circuit we can say that all resistance are added in parallel combination.

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

$\frac{1}{R_{eq}}=\frac{1}{R}+\frac{1}{2R}+\frac{1}{2R}=\frac{2+1+1}{2R}$

$R_{eq}=\frac{2R}{4}=R/2$.