The equivalent resistance of eight equal resistances in series is $48$ ohms. What would be the equivalent resistance if they are connected in parallel?

\frac{3}{4} Ω

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\frac{4}{3} Ω

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4 Ω

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3 Ω

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Solution

The correct option is C $\frac{3}{4} Ω$
Let the resistance of each resistor is $R$ .

In series we know, equivalent resistance is $R_{s} = n R = 8 R = 48 Ω$
$⟹ R = 6 Ω$

In paralle we know, equivalent resistance is $R_{p} = \frac{R}{n}$
$⟹ R_{p} = \frac{6}{8} = \frac{3}{4} Ω$

Answer-(A)

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The equivalent resistance of eight equal resistances in series is 48 ohms. What would be the equivalent resistance if they are connected in parallel?

The correct option is C 34ΩLet the resistance of each resistor is R.In series we know, equivalent resistance is Rs=nR=8R=48Ω⟹R=6ΩIn paralle we know, equivalent resistance is Rp=Rn⟹Rp=68=34ΩAnswer-(A)

The equivalent resistance of eight equal resistances in series is $48$ ohms. What would be the equivalent resistance if they are connected in parallel?

The correct option is C $\frac{3}{4} Ω$
Let the resistance of each resistor is $R$ .

In series we know, equivalent resistance is $R_{s} = n R = 8 R = 48 Ω$
$⟹ R = 6 Ω$

In paralle we know, equivalent resistance is $R_{p} = \frac{R}{n}$
$⟹ R_{p} = \frac{6}{8} = \frac{3}{4} Ω$

Answer-(A)