Question

The equivalent resistance of the network shown in the figure between the base terminals is

• A. $3\Omega$
• B. $3\frac{1}{2}\Omega$
• C. $2\frac{2}{3}\Omega$
• D. $2\Omega$

Answer 1

The correct option is C. $2\frac{2}{3}\Omega$.

As $1\Omega$ and $1\Omega$ are in series so their equivalent resistance is $2\Omega$ and this $2\Omega$ is in parallel in with another $1\Omega$.

Therefore their equivalent resistance is given by,

$r_{eq}=\frac{2\times 1}{2+1}=\frac{2}{3}\Omega$

Now $1\Omega$, $1\Omega$ and $\frac{2}{3}\Omega$ all are in series, therefore,

$R_{eq}=1+\frac{2}{3}+1=\frac{8}{3}\Omega$

$R_{eq}=2\frac{2}{3}\Omega$.