Question

The equivalent uniform rainfall depth of the catchment as shown in figure is _____ mm.

• A. 103.85

Answer 1

The correct option is A 103.85
$P_{avg}=\frac{P_1{A}_0+\left(\frac{P_1+P_2}{2}\right)A_1+\left(\frac{P_1+P_3}{2}\right)A_2\left(\frac{P_3+P_4}{2}\right)A_3+\left(\frac{P_4+P_5}{2}\right)A_4+P_5{A}_5}{A_0+A_1+A_2+A_3+A_4+A_5}$
$=\frac{70\times 60+\left(\frac{70+90}{2}\right)275+\left(\frac{90+100}{2}\right)260+\left(\frac{100+125}{2}\right)380+\left(\frac{125+140}{2}\right)215+140\times 40}{60+275+260+380+215+40}$
$=103.85mm$