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Question

The equivalent weight of a divalent metal whose chloride has vapour density equal to 60, is:

A
30
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B
49
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C
24.5
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D
16.5
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Solution

The correct option is B 49
Vapour density =Molecularwt.ofcompound2

Molecular wt. of chloride (MCl2)=2×60=120

[Metal is divalent, so two atoms of chlorine]

Molecular wt. of MCl2= Atomic mass of M + 2 × Atomic mass of chlorine

120=M+2(35.5)

12071=M=49

Equivalent wt =MolecularwtValency49224.5

Hence, option C is correct.

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