The equivalent weight of iron in $F e_{2} O_{3}$ would be:

18.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

26.66

No worries! We‘ve got your back. Try BYJU‘S free classes today!

112

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 18.6
Gram atomic weight of Iron is $56$ $g r a m s$ .

Oxidation state of Iron in $F e_{2} O_{3}$ is:
$2 x + 3 (- 2) = 0$
$⟹ x = 3$

It exists as $F e^{3 +}$ ion.

$∴ E q u i v a l e n t w e i g h t = \frac{G r a m A t o m i c w e i g h t}{O x i d a t i o n s t a t e} = \frac{56}{3} = 18.6$ $g r a m s$

Suggest Corrections

Similar questions

F e_{2} O_{3}

F e_{2} O_{3}

(F e = 56)

F e S_{2}

F e S_{2} \to F e_{2} O_{3} + S O_{2}

F e S_{2}

F e S_{2} + O_{2} \to F e_{2} O_{3} + S O_{2}

Join BYJU'S Learning Program