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Balancing Redox Equations

The equivalen...

Question

The equivalent weight of $K I O_{3}$ in the reaction
$2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I$ is

A

Mole wt.

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B

\frac{M o l . w t .}{6}

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C

\frac{M o l . w t .}{2}

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D

\frac{M o l . w t .}{3}

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Solution

The correct option is B $\frac{M o l . w t .}{6}$
$\frac{M o l e c u l a r w e i g h t}{6}$
The oxidation number changes from +5 to -1

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Q. The equivalent weight of

K I O_{3}

in the reaction

2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

2 C r (O H)_{3} + O H^{-} + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

The equivalent weight of

K I O_{3}

in the given reaction is:

Q. The equivalent weight of

K I O_{3}

in the reaction

2 C r (O H)_{3} + 4 O H + K I O_{3} \to 2 C r O_{4}^{2 -} + 5 H_{2} O + K I

Q. The equivalent mass of

K I O_{3}

in the reaction

2 C r {(O H)}_{3} + O H^{-} + K I O_{3} ⟶ 2 C r O_{4}^{2 -} + K I + 5 H_{2} O

$K M n O_{4}$ acts as an oxidising agent in the neutral medium and gets reduced to $M n O_{2}$ . The equivalent weight of $K M n O_{4}$ in neutral medium is ______ .

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