Question

The equivalent weight of $MnS{O}_4$ is half its molecular weight when it is converted to
(IIT-JEE, 1988)

• A. $M{n}_2{O}_3$
• B. $Mn{O}_2$
• C. $Mn{O}_4^{\ominus }$
• D. $Mn{O}_4^{2-}$

Answer 1

The correct option is B $Mn{O}_2$

$MnS{O}_4^{2-}\to Mn{O}_2+2e^{-}$
$\therefore$ Equivalent weight = M/2