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Redox Reactions and Couple

The equivalen...

Question

The equivalent weight of ${N a}_{2} S_{2} O_{3}$ as reductant in the reaction, ${N a}_{2} S_{2} O_{3} + H_{2} O + {C l}_{2} \to {N a}_{2} {S O}_{4} + 2 H C l + S$ is:

[Given: Molecular weight of $N a_{2} S_{2} O_{3}$ = M]

A

M /1

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B

M /2

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C

M /6

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D

M /8

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Solution

The correct option is D M /8
$N a_{2} S_{2} O_{3} + H_{2} O + C l_{2} ⟶ N a_{2} S O_{4} + 2 H C l + S$

$N a_{2} S_{2} O_{3}$ acts as a reductant to form $N a_{2} S O_{4}$ .

Oxidation state of $S$ $N a_{2} S_{2} O_{3}$ is $+ 2$

Oxidation state of $S$ in $N a_{2} S O_{4}$ is $+ 6$

$∴$ Change in oxidation state of $S = 4$

$∴$ Change in oxidation state of $N a_{2} S_{2} O_{3} = 8$

Equivalent weight = $\frac{M o l . w t}{8}$

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Similar questions

Q. The eq. wt. of

{N a}_{2} S_{2} O_{3}

as reductant in the reaction,

{N a}_{2} S_{2} O_{3} + H_{2} O + {C l}^{2} \to {N a}_{2} {S O}_{4} + 2 H C l + S

Q. In the reaction,

2 {N a}_{2} S_{2} O_{3} + I_{2} \to {N a}_{2} S_{4} O_{6} + 2 N a I

the equivalent weight of

{N a}_{2} S_{2} O_{3}

(m o l . w t . = M)

is equal to ______.

Q. The equivalent weight of

{N a}_{2} S_{2} O_{3}

in the following reaction is

2 {N a}_{2} S_{2} O_{3} + I_{2} ⟶ {N a}_{2} S_{4} O_{6} + 2 N a I

Q. If the molecular wt. of

{N a}_{2} S_{2} O_{3}

I_{2}

M_{1}

M_{2}

respectively then what will be the equivalent weight of

{N a}_{2} S_{2} O_{3}

I_{2}

in the following reaction?

2 S_{2} O_{3}^{2 -} + I_{2} ⟶ S_{4} O_{6}^{2 -} + 2 I^{-}

Q. The density of

3 M

solution of sodium thiosulphate (

{N a}_{2} S_{2} O_{3})

1.56 g / m L

. Calculate
(i) amount of

{N a}_{2} S_{2} O_{3}

in % w/w
(ii) mole fraction of

{N a}_{2} S_{2} O_{3}

(iii) Molality of

{N a}^{+}

S_{2} O_{3}^{2 -}

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