The equivalent weight of $N a H_{2} P O_{4}$ in the following reaction is:
$N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O$

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100

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120

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Solution

The correct option is B 120
An equivalent weight of an acid is the ratio of the molecular weight to the number of replaceable $H$ atoms. In the reaction, only one $H$ atom of phosphoric acid is displaced. Hence, the equivalent weight is equal to molecular weight which is 120 g/mol of hydrogen (atomic weight of phosphorus =31).

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Similar questions

(H_{3} P O_{4})

N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O

H_{2} P O_{4}

N a O H + H_{2} P O_{4} \to N a H_{2} P O_{4} + H_{2} O

H_{3} P O_{4}

H_{3} P O_{4} + N a O H \to N a H_{2} P O_{4} + H_{2} O

H_{3} P O_{4}

H_{3} P O_{4} + N a O H \to N a H_{2} P O_{4} + H_{2} O

(H_{3} P O_{4})

N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O

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