You visited us 5 times! Enjoying our articles? Unlock Full Access!

Reaction with Metals

The equivalen...

Question

The equivalent weight of $S O_{2}$ in the given reaction $S O_{2} + H_{2} S \to S + H_{2} O$ is :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 16
The molecular weight of $S O_{2}$ is $64$ g/mol.
The oxidation number of $S$ changes from $+ 4$ to $0$ .
The change in the oxidation number of $S$ is $4$ .
The equivalent weight of $S O_{2}$ is $Equivalent weight = \frac{Molecular weight}{Change in the oxidation number}$
$Equivalent weight = \frac{64}{4}$
$Equivalent weight = 16$

Suggest Corrections

Similar questions

S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O

S O_{2}

H_{2} S

S

1

S O_{2}

2

H_{2} S

3

2

H_{2} O

H_{2} S + \frac{3}{2} O_{2} \to H_{2} O + S O_{2},

Δ H = - 136.7 K c a l

H_{2} + \frac{1}{2} O_{2} \to H_{2} O, Δ H = - 68.4 K c a l

S + O_{2} \to S O_{2}, Δ H = - 71 K c a l

Δ H_{f} o f H_{2} S

N O_{3}^{⊝} + A s_{2} S_{3} + H_{2} O \to A s O_{4}^{3 -} + N O + S O_{4}^{2 -} + H^{⨁}

A s_{2} S_{3}

M

S O_{2}

S O_{2} + C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l

S O_{2}

S

S O_{2}

8

S

S O_{3}

Join BYJU'S Learning Program