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Oxidising Reagent and Reducing Reagent

The equivalen...

Question

The equivalent weight of the underlined compound by taking its molecular weight as $M$ is:

$N H_{4} {N O}_{3} - --------- - ⟶ N_{2} O + 2 H_{2} O$

A

E = \frac{M}{4}

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B

E = \frac{M}{3}

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C

E = \frac{M}{2}

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D

None of these

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Solution

The correct option is D None of these
$\begin{matrix} N H_{4} N O_{3} ⟶ N_{2} O + 2 H_{2} O Change in Oxidation number of Nitrogen = 1 Equivalent weight = M \end{matrix}$ (+5 to +4)

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