You visited us 4 times! Enjoying our articles? Unlock Full Access!

Mole Concept

The equivalen...

Question

The equivalent weight of the underlined compound is $(50 + x)$ . Find the value of $x$ :

${N a}_{2} {C O}_{3} + H_{2} S O_{4} ⟶ {N a}_{2} S O_{4} + H_{2} O + {C O}_{2}$

Open in App

Solution

$\begin{matrix} Equivalent weight of {N a}_{2} {C O}_{3} = \frac{Molecular w e i g h t}{2} = 53 50 + x = 53 x = 3 \end{matrix}$ (molecular weight of $N a_{2} C O_{3}$ is 106)

Suggest Corrections

Similar questions

(80 + x)

x

N a H {C O}_{3} - --------- - + H C l ⟶ N a C l + H_{2} O + {C O}_{2}

H_{2} S O_{4}

H_{2} S O_{4} + N a I \to N a_{2} S O_{4} + I_{2} + H_{2} S + H_{2} O

250 m L

{N a}_{2} {C O}_{3}

2.65 g

{N a}_{2} {C O}_{3} \cdot 10 m L

x

m L

0.001 M

{N a}_{2} {C O}_{3}

x

{N a}_{2} {C O}_{3} = 106

(90 + x)

x

2 C_{6} H_{5} O H - --------- - + 2 N a ⟶ 2 C_{6} H_{5} N a + H_{2}

{N a}_{2} {C O}_{3} + {C O}_{2} + H_{2} O ⟶

Join BYJU'S Learning Program