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Mole Concept

The equivalen...

Question

The equivalent weight of the underlined compound is $(50 + x)$ . Find the value of $x$ :

${N a}_{2} {C O}_{3} + H_{2} S O_{4} ⟶ {N a}_{2} S O_{4} + H_{2} O + {C O}_{2}$

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Solution

$\begin{matrix} Equivalent weight of {N a}_{2} {C O}_{3} = \frac{Molecular w e i g h t}{2} = 53 50 + x = 53 x = 3 \end{matrix}$ (molecular weight of $N a_{2} C O_{3}$ is 106)

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