The equivalents of $H_{2} O_{2}$ reacted with $S n^{2 +}$ is:

0.2

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0.3

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0.4

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0.6

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Solution

The correct option is D $0.6$
The $n$ factor for both $H_{2} O_{2}$ and $S n^{2 +}$ is $2$ .
$2 H^{⊝} + H_{2} O_{2} + S n^{2 +} \to S n^{4 +} + 2 H_{2} O$
Millimoles of $H_{2} O_{2} =$ Millimoles of $S n^{2 +}$
$= 100 \times 3 = 300$ mmol
$= 300$ mmol of $H_{2} O_{2}$
$= 300 \times 2$ (n-factor) meq. $H_{2} O_{2}$
$= 600$ meq. $= 0.6$ eq.

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