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Question

The escape velocities on two planets of masses m1 and m2, having same radius, are v1 and v2 respectively, then

A
v1v2=m1m2
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B
v2v1=m1m2
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C
v1v2=(m1m2)2
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D
v1v2=m1m2
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Solution

The correct option is D v1v2=m1m2
ve=2GM/R
Thus,
v1/v2=m1/m2

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