The escape velocity at the surface of earth can be expressed as:
$v_{e} = \sqrt{\frac{2 G M}{R}}$ .

22 km / s

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Solution

The correct option is A
22 km / s

The escape velocity $(v_{e})$ is the minimum speed needed for an object to escape from the gravitational influence of Earth.
It is given by $v_{e} = \sqrt{\frac{2 G M}{R}}$
The escape velocity from the earth is about 11.186 km/s.

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The escape velocity at the surface of earth can be expressed as: ve=√2GMR.

The correct option is A 22 km / s The escape velocity (ve) is the minimum speed needed for an object to escape from the gravitational influence of Earth. It is given by ve=√2GMR The escape velocity from the earth is about 11.186 km/s.

The escape velocity at the surface of earth can be expressed as:
$v_{e} = \sqrt{\frac{2 G M}{R}}$ .

The correct option is A
22 km / s

The escape velocity $(v_{e})$ is the minimum speed needed for an object to escape from the gravitational influence of Earth.
It is given by $v_{e} = \sqrt{\frac{2 G M}{R}}$
The escape velocity from the earth is about 11.186 km/s.