Question

The escape velocity for a body projected vertically upwards from the surface of the earth is $11.2km{s}^{-1}$. It the body is projected in a direction making an angle of $45$${}^{\circ }$ with vertical, the escape velocity will be

• A. $11.2km{s}^{-1}$
• B. $11.2\times \sqrt{2}km{s}^{-1}$
• C. $11.2\times 2km{s}^{-1}$
• D. $11.2/\sqrt{2}km{s}^{-1}$

Answer 1

The correct option is A $11.2km{s}^{-1}$

Escape velocity is independent of the angle of projection.so,the escape velocity for angle of projection ${45}^0$ will also be $11.2k$$m{s}^{-1}.$
hence,option A is correct.