Question

The escape velocity for a body projected vertically upwards from the surface of the earth is $11.2km{s}^{-1}$ . If the body is projected in a direction making an angle of ${45}^o$ with the vertical, the escape velocity will be:

• A. $11.2km{s}^{-1}$
• B. $11.2\times \sqrt{2}km{s}^{-1}$
• C. $11.2\times 2km{s}^{-1}$
• D. $11.2/\sqrt{2}km{s}^{-1}$

Answer 1

The correct option is A $11.2km{s}^{-1}$

Escape velocity of body is independent of the angle of projectile. Hence charging the angle of projection is not going to affect the angle the magnitude of escape velocity therefore escape velocity is $11.24m/s$.