The escape velocity for any satellite to be placed in a orbit is :

11.2 k m s^{- 1}

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11 k m s^{- 1}

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22 k m s^{- 1}

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22.2 k m s^{- 1}

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Solution

The correct option is B $11.2 k m s^{- 1}$
The escape velocity on a planet of radius $R$ is given by ,
$v_{e} = \sqrt{2 g R}$
for earth - $R = 6.4 \times 10^{3} k m, g = 9.8 m / s^{2}$
hence $v_{e} = \sqrt{2 \times 9.8 \times 6.4 \times 10^{3}} = 11.2 k m s^{- 1}$

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The escape velocity for any satellite to be placed in a orbit is :

The correct option is B 11.2 kms−1The escape velocity on a planet of radius R is given by , ve=√2gR for earth - R=6.4×103km,g=9.8m/s2hence ve=√2×9.8×6.4×103=11.2kms−1

The correct option is B $11.2 k m s^{- 1}$
The escape velocity on a planet of radius $R$ is given by ,
$v_{e} = \sqrt{2 g R}$
for earth - $R = 6.4 \times 10^{3} k m, g = 9.8 m / s^{2}$
hence $v_{e} = \sqrt{2 \times 9.8 \times 6.4 \times 10^{3}} = 11.2 k m s^{- 1}$