The escape velocity from a planet of mass (M), radius (R) and acceleration due to gravity (g) is given by:

2 \sqrt{\frac{G M}{R}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2 g R}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{\frac{2 g M}{R}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{\frac{2 G M}{R}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
B $\sqrt{2 g R}$
D $\sqrt{\frac{2 G M}{R}}$

Suggest Corrections

Similar questions

Q. Acceleration due to gravity

g

near the surface of a planet of mass

M

and radius

R

is given by:

G

is the Universal constant.

Q. Density of a spherical planet of radius R is given by

ρ = ρ_{0} (1 + \frac{r}{R})

where r is distance from center of planet, then

Q. Escape velocity from a planet of mass

M

and radius

R

will be:

If mass of earth is M, radius is R and gravitational constant is G, then work done to take 1 kg mass from earth surface to infinity will be

At what absolute temperature $T$ is the root mean square speed of a hydrogen molecule equal to its Escape velocity from the surface of the moon? The radius of moon $R = g$ is the acceleration due to gravity on moon's surface $m$ is the mass of a hydrogen molecule and $k$ is the Boltzmann constant

Join BYJU'S Learning Program

The escape velocity from a planet of mass (M), radius (R) and acceleration due to gravity (g) is given by:

The correct options are B √2gR D √2GMR

The correct options are
B $\sqrt{2 g R}$
D $\sqrt{\frac{2 G M}{R}}$